The length of a rectangle is 2 centimeters less than its width. What are the dimensions of the rectangle if its area is 63 square​ centimeters?

Answer 1

Let w = width. &. L = length = w-2. (Given)

Area = L x w = w(w-2) = w^2 -2w = 63. Or. W^2-2w-63 = 0

Solving for w we get w = -7 and 9. (Discard -7)

so width = 9 & length = 7