Tom K. answered 02/27/19
Knowledgeable and Friendly Math and Statistics Tutor
Let the speed of the plane be p and the speed of the wind be w.
The speed of the plane with the wind is p + w; the speed against the wind is p -w
1 hour 50 min = 110 min.
2 hr 10 min = 130 min
distance travelled is 715 miles
rt = d
Thus,
(p+w) 110 = 715
(p-w) 130 = 715
Expanding,
110 p + 110 w = 715
130 p - 130 w = 715
Multiply the bottom equation by 11/13
110 p - 110 w = 715 * 11/13
Subtract the bottom equation from the top equation
220w = 715 * 2/13
w = 715 * 2/13/220
w = 5 * 11 * 13 * 2/13/(2*2*5*11) = 1/2
130 p = 715 + 130 w
130 p = 715 + 130 * 1/2
130 p = 780
p = 6
p = 6 miles/min = 360 mph
w = 1/2 mile/min = 30 mph