Pranav P. answered • 06/09/19
Tutor
New to Wyzant
Learned Algebra 1 7 years ago and tutored Algebra 1 for 4 years
f(x) = 500 (2)x
An exponential function is written in the form of f(x) = a (b)x. When we want to find an initial value of 500, it means that when x = 0, then y must equal 500. So, you plug in 0 to x in the exponential function, which leaves you with f(0) = a. Then, since f(0) = 500, that means a = 500. We can then plug this into the original function so that f(x) = 500(b)x. Since any nonzero number to power of 0 is 1, b can be any number, we can set b to 2. Therefore, the answer to the question would be f(x) = 500 (2)x.
