PLEASE HELP!!!! i need to know how to do these

Question

Find three consecutive odd integers such that -3 times the sum of the first and third is 50 greater than 8 times the opposite of the second.

Answer 1

Hello Dasany.

Let A = first odd number

A + 2 = second consecutive odd number

A + 4 = third consecutive odd number

(-3) (A + (A + 4) = Negative 3 times the sum of the 1st and 3rd

consecutive odd numbers

(8) (-(A + 2)) + 50 = Fifty more than 8 times the opposite

of the 2nd consecutive odd number

Therefore, our equation is:

(-3) (A + (A + 4) = (8) (-(A + 2)) + 50

-3A -3A -12 = (8) (-A - 2) + 50

-6A - 12 = -8A - 16 + 50

-6A - 12 = -8A + 34

8A - 6A = 34 + 12

2A = 46

A = 23 which is the 1st odd number.

A + 2 = 23 + 2 = 25 = 2nd consecutive odd number

A + 4 = 23 + 4 = 27 = 3rd consecutive odd number

ANSWER: 23, 25, 27

CHECKING:

(-3) (23 + 27) = (-3) (50) = -150

(8) (-25) + 50 = -200 + 50 = -150

Hope this is helpful to you Dasany.