a toltal of 171 dogs competed in 3 days on the first day 87 dogs competed twice as many competed on the second than third day

Question

how many dogs competed on the second and third days?

Answer 1

let x be the number that competed on the 3rd day

2x is the number that competed on the 2nd day

1st day + 2nd day +3rd day = total number of dogs

87+2x+x=171

Subtract 87 from both sides and combine like terms

87+2x+x-87=171-87

3x=84

Divide both sides by 3

3x/3=84/3

x=28 (3rd day)

2x = 2(28) = 56 (2nd day)