the product of two consecutive odd integers is 59 more than twice their sum.

Question

Using the factoring method or the quadratic formula, How can I set up an equation and solve it to find the solutions.

Answer 1

I think I answered this question elsewhere last night.

Let the 2 numbers be 2n-1 and 2n+1

Product = 4n²-1

Sum = 4n

Therefore 4n²-1 = 8n + 59

4n² - 8n -60 = 0

n² - 2n -15 = 0

(n-5)(n+3)=0

Once you have 2 possible values for n, you will get 2 pairs for the numbers.