J.R. S. answered 02/25/19
Ph.D. University Professor with 10+ years Tutoring Experience
To transfer thermal energy to the surrounding, ∆H must be negative
To perform pressure-volume work, the pressure or volume must change.
1) and 5) have positive values of ∆H, so they are out
2 has negative ∆H and since a gas is formed (no gas on reactant side), the pressure or volume would increase. So, this reaction is a "yes".
3) has negative ∆H but no change in the moles of gas from reactant to products (1 mole on each side), so this would be a "no".
4) negative ∆H but a decrease in moles of gas from reactant to product side, so PV work is in the wrong direction.