whta is the domain and range of y=(-16x^2)+16

Answer 1

This is really an algebra problem....

y=f(x)= -16x^2)+16

Factor out -16:

y= -16(x^2-1)

factor (x^2-1) into (x+1)(x-1)

So since there is no restriction on what x could be, then the domain is {-infinity < x < infinity}

The graph is a parabola pointing upward, and the vertex is at (-b/2a,f(-b/2a)). In this equation, a= -16, b=0, & c=16

so vertex is at (0,16), so the range is { -infinity < y <=16)