A certain rectangle has a width which is one - third of the length. The per,meter is 20 find the length and width.

Answer 1

Greetings! Lets solve this shall we?

Let the width be equal to (1/3)x, where the length is just x.

The perimeter is 20 so the perimeter equation is

2(x) + 2(1/3)(x) = 20

2x + (2/3)(x) = 20

(6/3)x + (2/3)x = 20...................from obtaining the common denominator. Then,

(8/3)x = 20.................Now we take the reciprocal of (8/3) to both sides to solve for x

x = 20(3/8)

x = 7.5

So, the length is 7.5 and the width is (1/3)(7.5) = 2.5

I hope this helped!