
Victoria V. answered 02/20/19
Math Teacher: 20 Yrs Teaching/Tutoring CALC 1, PRECALC, ALG 2, TRIG
These types of word problems create two different equations: 1 for the number of questions and one for the score.
Looking at the number of questions first: There are 7-point questions (we will call "S") and there are 2-point questions (we will call "T") and since all of the questions are either 7-oint or 2-point, then the number of 7-point question and the number of 2-point questions must add up to 35, because there are 35 questions on the test. This, algebraically is:
S + T = 35
Now we look at the points. Each 7-point question contributes 7 points toward the total number of points (which is 100) and each 2-point question contributes 2 points toward the total. So algebraically that is:
7S + 2T = 100
This is the system of equation that must be solved.
S + T = 35
7S + 2T = 100
Multiply top equation by -2.
-2S + -2T = -70
7S + 2T = 100
Add vertically and the "T"s cancel out, leaving
5S = 30
Divide both sides by 5
S = 6 So there are six 7-point questions
Substitute "6" in for "S" in the equation: S + T = 35
6 + T = 35
Subtract 6 from both sides and find that
T = 29 So there are twenty-nine 2-point questions.
CHECK: Does S + T = 35? (6 + 29 = 35? YES, so works in top equation)
Does 7S+2T=100? (7(6) + 2(29) = 42 + 58 = 100? YES so works in bottom equation)
So we have found the correct solution. :-)