Maths, I need help

Question

Find the last 2 digits of 2005^1+2005^2...+2005^2005

Answer 1

I believe the answer is 39.

The sum will be 2005(2005²⁰⁰⁵ -1)/2004

The exponential will end in a 5 and the term in parentheses will end in a 4 which will divide into the denominator to give 51. 51 divided into 2005 ends in 39.

Please let me know if this is not correct.