A rectangle has a length of 32 feet less than eight times it’s width. If the area of the rectangle is 96 square feet find the length of the rectangle

Answer 1

L = 8w-32

w(8w-32) = 96

8x^2 - 32w - 96 = 0

w^2 - 4w - 12 = 0

(w - 6)(w + 2 ) = 0

w+2=0 results in negative measures

w-6=0 ---> w = 6

width is 6

length is 8(6) - 32 = 48-32 = 16