When 1.0 g of snack cake is combusted in a constant-volume bomb calorimeter with a heat capacity (including its water) of 10.0 kJ/°C, the temperature of the calorimeter rises by 2.24°C.

Question

When 1.0 g of snack cake is combusted in a constant-volume bomb calorimeter with a heat capacity (including its water) of 10.0 kJ/°C, the temperature of the calorimeter rises by 2.24°C. How many nutritional calories (Calories) are in one serving (28 g) of this snack cake?

(1 Calorie = 1000 calories and 1 calorie = 4.184 J)

Please show steps.

**the heat capacity of the calorimeter includes the water in it, so the (m s ΔT) component of of qsystem = − {(Ccalorimeter ΔT) + (m s ΔT)} can be ignored.

I got cΔT = (10.0 kJ/°C)(2.24°C) = 22.4 kJ * 28 = 627.2 kJ and converted this to Calories. For my final answer I got 149.904 Calories, which is about 150 Calories. Is my work correct?

Answer 1

Yes, you did this problem correctly. Nice job.