Word problems..

Question

Mukul has $3.55 in quarters, dimes and nickels in his pocket. He has three more dimes than quarters and nine more nickels than quarters. How many of each coin are in his pocket

Answer 1

Greetings! Lets solve this shall we?

This problem is more of knowing how to convert the words in a word problem into a mathematical equation! So lets do that!

Let,

x = quarters

(x+3) = dimes

(x+9) = nickels

Also, note that a quarter is 0.25, a dime is 0.10 and a nickel is 0.05. Then, the equation is set up as

0.25x + 0.05(x+9) + 0.10(x+3) = $3.55.............................................Now we can solve for x ! Then, we use the Distributive Property to solve for x. So

0.25x + 0.05x + 0.45 + 0.10x + 0.3 = 3.55

0.40x + 0.75 = 3.55....................Then we subtract 0.75 to both sides such that

0,40x = 2.80.......................Then we solve for x by dividing 0.40 such that

x = 7.

Now recall that

x = quarters...........7 Quarters

(x+3) = dimes...(7+3) = 10 dimes

(x+9) = nickels..(7+9) = 16 nickels

I hope this helped!