What the answer to sqrt128x^7y^9?

Answer 1

I assume the problem looks like this:

If so, write 128 as the product of a perfect square (4, 9, 16, 25, 36, 49, 64,etc) if possible. It turns out to be 64 *2. Write x7 as the product of a perfect square, That can be written as x*x6 (x3 * x3 = x6). Write y9 as a product of a perfect square. That can be written as y*y8 (x4 * x4 = x8). Then you have this:

Now take the square root of all the perfect squares and leave the rest.