The product of the first and third of three consecutive integers is 3 more than three times the second integer find the integers

Answer 1

1st is x

2nd is x+1

3rd is x+2

x(x+2) = 3(x+1)+3

x^2 + 2x = 3x + 3 + 3

x^2 + 2x = 3x + 6

x^2 -x - 6 = 0

( x - 3 )( x + 2 ) = 0

x=3 or x = -2

-2, -1, and 0 OR 3,4, and 5