Pre calc help please

Question

assume the given point is on the terminal side of an ane in standard position. determine the exact values of the six trigometric functions of the angle: (6, -12)

Answer 1

In the 4th quadrant

Pythagorean says the hypotenuse is sqrt ( 144+36) = sqrt(180) = 6 * sqrt(5)

sine is -12/6 * sqrt(5) = -2/sqrt(5) = -2*sqrt(5)/5 = (-2/5) * sqrt(5)

cosine is 6/6*sqrt(5) = 1/sqrt(5) = sqrt(5)/5 = (1/5)*sqrt(5)

tangent is -12/6 = -2

cosecant is 5 / (-2 * sqrt(5)) = 5 * sqrt(5) / -10 = sqrt(5)/(-2) = (-1/2)*sqrt(5)

secant is 5/sqrt(5) = 5*sqrt(5)/5 = sqrt(5)

cotangent is -1/2