
Lauren H. answered 02/11/19
Experienced High School Chemistry Teacher
j/s = 2/3, j = (2/3)s
j - 32 = (s - 32)(3/5)
Substitute:
(2/3)s - 32 = (s - 32)(3/5)
(2/3)s - 32 = (3/5)s - (96/5)
(10/15)s - (160/5) = (9/15)s - (96/5)
(1/15)s = (64/5)
s = (64/5)(15)
s = 192
j/192 = 2/3
3j = 2(192)
j = 128