Patrick B. answered 02/11/19
Math and computer tutor/teacher
y is the base measure.
Perimeter P = 30 = 2x+y
y = 30 -2x
Dropping height h to the base produces 2 congruent right triangles
with hypotenuse x, and legs y/2 and h
Pythagorean says sqrt ( x^2 - (y/2)^2) = h
sqrt ( x^2 - (1/4)y^2) = h
sqrt( x^2 - (1/4) ( 30 -2x)^2) = h
sqrt( x^2 - (1/4) ( 900 - 120x + 4x^2) = h
sqrt( x^2 - 225 + 30x - x^2) = h
sqrt( 30x - 225) = h
The area is (1/2) y h =
(1/2) ( 30 -2x) sqrt(30x - 225) = A(x)