Find linear equation whose graph is straight Line with given properties. Through (3,18) with slope 6

Answer 1

You are given a line with a slope and a point, so the best method would be to use the point-slope equation of a line which is y = mx + b, where x & y are the coordinates of any point on a line, m is the slope of that line and b is the y-intercept of that line we know x, y and m, but not b, so we must find b first:

x = 3

y = 18

m = 6

b = ?

y = mx + b

18 = 6(3) + b

18 = 18 + b

0 = b

y = mx + b

y = 6x + 0

y = 6x <-----your answer!

Hope this helps!