Francisco P. answered 11/05/14
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Well-Versed in Calculus
The tangent line approximation would include the point (0,1) since ex goes through it.
To find the tangent line, we would also need to find the slope. We can do this by taking the derivative of y = ex and evaluating it at x = 0.
y' = dy/dx = ex
slope = ex|x=0 = 1
Equation of tangent line through (0,1): y - 1 = 1(x - 0)
y = x + 1