A sample of 0.400 L Ne initially at 1.50 atm and 240.ºC is mixed with a 0.150 L sample of O2 initially at 550. torr and 130.ºC in a 500. mL flask held at 25.0ºC. Find the total pressure in the flask.

Question

A sample of 0.400 L Ne initially at 1.50 atm and 240.ºC is mixed with a 0.150 L sample of O₂ initially at 550. torr and 130.ºC in a 500. mL flask held at 25.0ºC. Find the total pressure in the flask?

Please show steps.

Answer 1

Total pressure = P_Ne + P_O2

Using P1V1/T1 = P2V2/T2 and T2 = 0.400 L + 0.150 L = 0.550 L we have....

For Ne: (1.50 atm)(0.400 L)/513 = (P2)(0.550 L)/298 Solve for P2 which will be P_Ne

For O₂: (0.724 atm)(0.150 L)/403 = (P2)(0.550 L)/298 Solve for P2 which will be P_O2 (note ∆ mm to atm)

Add the P_Ne + P_O2 to get total pressure of the mixture.