
Doug C. answered 02/06/19
Math Tutor with Reputation to make difficult concepts understandable
Let x = first #, y=2nd #, z=3rd#
Then x + y + z = 95 (sum of the three numbers is 95)
z = 3x (3rd is 3 times first)
y = x + 10 (2nd is 10 more than first).
Now substitute into the first equation:
x + (x +10) + 3x = 95 ((x+10 replaces y; 3x replaces z)
5x + 10 = 95
5x=85
x = 17
y= 27
z = 51
Check to make sure these values add to 95.