Complete the square to rewrite y= X^2 + 8x+7 in vertex form, and then identify the mininum y-value of the function

Question



Answer 1

y = x² + 8x + 7

Add [(1/2)(8)}² = 16 to both sides to obtain y + 16 = (x² + 8x + 16) + 7

y + 16 = (x+4)² + 7

y = (x+4)² - 9

Vertex (lowest point on the graph) is (-4,-9).

Minimum y-value = -9.