The length of a rectangle is 5 m less than double the width and the area of the rectangle is 52m^2. Find the dimensions of the rectangle

Answer 1

L = 2w-5

Area = w * L

52 = w(2w-5)

52 = 2w^2 - 5w

0 = 2w^2 - 5w - 52

0 = ( 2w - 13 )( w + 4 )

w+4=0 results in negative measures

2w-13 = 0 ---> w = 13/2 = 6.5

----> L = 2(6.5)-5 = 13 - 5 = 8

Length is 8 and width is 6.5