use the remainder theorem to find P(-3) for P(x)=2x^4+6x^3-4x-8. specifically, give the quotient and the remainder for the associated division and the value of P(-3).

Question

Quotient=

Remainder=

P(-3)=

Answer 1

Greetings! Lets solve this shall we?

So, we must find the

Quotient=

Remainder=

P(-3)=

such that P(-3) means x = -3. Then the factor becomes x+3 after adding 3 to both sides of the equal sign. Now we can find the quotient

(2x⁴+6x³-4x-8) / (x+3) = (2x³ - 4) + (4 / (x+3)), where the

Quotient = 2x³ - 4

Remainder = 4

P(-3) = 4

I hope this helped!