the length of a rectangle is 11 feet longer then 3 times its width. if the perimeter is 38 feet, how long is the length?

Question

a math problem i cant do :(

Answer 1

Greetings! Lets solve this shall we ?

So, let the perimeter yield P = 2l + 2w, where w = x and l = 3x + 11 and P = 38 such that

2(3x+11) + 2x = 38 ..............Now we solve for x to obtain the length of the rectangle, first distributing 2 such that

6x + 22 + 2x = 38............Add like terms such that

8x + 22 = 38...............Now subtract 22 such that

8x = 16............Divide 8 such that

width = x = 2

Now the length must be l = 3(2) + 11 = 17 feet

I hope this helped!