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Question

A rectangular painting measures 15“ x 17“ and contains a frame of uniform with around the four edges the perimeter of the rectangle foreign by the painting and it’s frame is 96 determine the width of the frame

Answer 1

Let w be the width of the frame.

The augmented rectangle (picture and frame) has dimensions (15+2w) and (17+2w)

2(15+2w) + 2(17+2w) = 96 <--- perimeter of framed picture

30 + 4w + 34 + 4w = 96

8w + 64 = 96

8w = 32

w = 32/8 = 4