find three consecutive odd integers such that three times the sum of the first two integers exceeds four times the third by 12

Question

find three consecutive odd integers such that three times the sum of the first two integers exceeds four times the third by 12. PLZ HELP ME!!!

Answer 1

Let x equal the first odd integer in the series.

The three consecutive odd integers would be represented by x, then x+2, followed by x+4.

So, 3(x+x+2)=4(x+4) +12

Solve for x.

The three numbers are 11,13,15.