Denise G. answered 11/05/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
The conjugate of this would be 1/5-i To multiply these you get:
(1/5-i)(1/5+i) You multiply these by FOIL
F = (1/5)(1/5) = 1/25
O = (1/5)(i) = 1/5i
I = (1/5)(-i) = -1/5i
L = (-i)(i) = -i2
Adding them together:
1/25+1/5i -1/5i -i2 Simplify
1/25-(-1)
1/25+1
1/25+25/25 = 26/25