Find four consecutive integers so that twice the first decreased by three times the third is -27

Answer 1

The integers are X,X+1,X+2,X+3

2X - 3(X+2) = -27

2x - 3x - 6 = -27

2x - 3x = -21

-x = -21

x=21

they are:

21,22,23,24

check:

2(21) - 3(23) = 42 - 69 = -27

Answer 2

You could give individual variable names to these four consecutive integers, or you simply call the lowest integer x.

They are:

x

x+1

x+2

x+3

now, read the problem statement:

2x - 3(x+2) = -27

2x -3x - 6 = -27

-x = -21

x = 21

The consecutive integers are 21, 22, 23, 24

Checking (very important):

Is 2(21) - 3(23) = - 27 ?

42 - 69 = - 27 ?

-27 = - 27 ?yes