help meeeeeeeeeee

Question

find all possible pairs of consecutive odd integers whose sum is equal to their product decreased by 47

Answer 1

If x is an odd integer, the next consecutive odd integer is x+2. Example, if x = 3, then the next odd integer is 3+2 = 5.

The sum of the consecutive odd integers is x + (x + 2) = 2x + 2

Their product decreased by 47 is x(x+2) - 47 = x² + 2x - 47

2x + 2 = x² + 2x - 47

0 = x² - 49

Solve for x. There are two pairs of consecutive integers that solve the problem.