The perimeter of a rectangle is 88 cm. If one dimension is 4 less than 3 times the length of the other dimension, what are the two side lengths?

Answer 1

Equation for perimeter of a rectangle with sides of length x and y and perimeter 88 is

2x+2y = 88

The condition one dimension(y) is(=) 4 less than 3 times the length of the other dimension(x) yields the equation

y = 3x - 4

Now, substitute y in the primeter equation with this equation derived from the problem. We get

2x + 2(3x - 4) = 88

Solving for x we get

2x + 6x - 8 = 88

8x - 8 = 88

8x -8 + 8 = 88 + 8

8x=96

8x/8=96/8

x=12

Now we substitute the value of x in the y equation to get the value of y

y=3(x) - 4

y=3(12)-4

y=36-4

y=32

Verify he perimeter equation

2(12) + 2(32) = 88

24 + 64 = 88

88=88

So, the answer to the problem is:

The two side lengths of the rectangle are 12cm and 32 cm.