Write an equation of the line that goes through the point (3,7) and is perpendicular to the line y=-3x+6

Question

Write an equation of the line that goes through the point (3,7) and is perpendicular to the line y=-3x+6

Answer 1

The slope of the given line is -3.

Perpendicular lines have slopes that are NEGATIVE RECIPROCALS.

The perpendicular line has slope 1/3

(3,7) means x=3 and y = 7

y = Mx + b

7 = (1/3)(3) + b

7 = 1 + b

b = 6

y = (1/3)x + 6