Need help ASAP!!! What is the equation of the line perpendicular to 3x+y= -8 that passes through (-3,1) ?

Question

Please Need help ASAP!!! What is the equation of the line perpendicular to 3x+y= -8 that passes through (-3,1) ?

Answer 1

The equation is given in Standard Format (Ax+By=C).

You may solve for y, once and forever, and remember that m, the slope in y=mx+b, is=(-A/B).

The slope of all perpendicular lines is the negative inverse, that is (B/A)

The equation of the perpendicular line is: (-1/3)x + y = C and we need point (-3,1) to solve for C.

(-1/3)(-3)+1 = C

2 = C

The equation of the line is (-1/3)x + y = 2.

However, by convention,Standard Form has integer coefficients and the x coefficient is positive. So, the equation is:

x - 3y = -6 [multiply all by (-3)]

Check: the slope is +1/3, which is the negative reciprocal of (-3).

Is (-3,1) on the line?

(-3) - 3(1) = -6 ?

-6 = -6 >yes