if a and b are real numbers such that a+b=a-b, what is the value of a/\2•b+a+b-ab/\2 divides by a-b

Answer 1

a+b = a-b

b = -b

b+b = 0

2b = 0

b=0

So then

(a^2*b + a + b - a*b^2 )/(a-b) =

a /a = <--- any term containing b=0 cancels out, by multiplying by b=zer0

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