What is an equation of the line that passes through the point (-3,4) and is parallel to the line x−3y=27?

Answer 1

x - 3y = 27

x -3y - 27 = 0

x - 27 = 3y

(1/3)x - 9 = y

the slope of the given line is 1/3

Parallel lines have the same slope.

So, the slope of the parallel line is also 1/3

y = (1/3)X + b

(-3,4) means x=-3 and y=4

4 = (1/3)(-3) + b

4 = -1 + b

b = 5

y = (1/3)x + 5