Patrick B. answered 12/31/18
Math and computer tutor/teacher
I have already solved this problem for you.
P = (9/20) * d + 15
P = (17/4) * t + 15
Blah B.
asked 12/30/18At the surface of the ocean, the water pressure on the submarine is the same as the air pressure above the water-about 15lb/in^2. Below the surface, the water pressure increases by about 9lb/in^2 for every 20 ft of descent. Part A Write an equation in slope-intercept form showing the pressure p, in pounds per square inch, on the submarine at different depths d, in feet. Then graph the equation. Part B On another dive, the submarine descends at a steady rate from sea level. After 20 s the pressure gauge reads 100 lb/in^2.What is the rate of descent for the submarine? Show the steps of your solution.If necessary, round your answer to the nearest tenth. I really need help and have it due today. Please help ASAP.
Patrick B. answered 12/31/18
Math and computer tutor/teacher
I have already solved this problem for you.
P = (9/20) * d + 15
P = (17/4) * t + 15
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