David W. answered 12/30/18
Experienced Prof
P and Q individually completes a work in 15 and 25 days respectively.In How Mny Days P And Q Can Complete the work if they start working on alternate days. Starting From P And Q?
The "key" to understanding "work together" problems is to realize that rate may be either hours per job (that is, hr/job) or jobs per hour (that is, job/hr).
So, "P completes a work in 15 days" means 1/15 work/day or 15 days/work.
So, to complete 1 total work, if P and Q worked the same number of days, x,
x/15 + x/75 = 1
5x/75 + 3x/75 = 1
8x/75 = 1
x = 75/8
x = 9.375 days each
But, Q might have worked 1 day less than P., so
day who amt. total
------ ------ ----- -----
1 P 5/75 5/75
2 Q 3/75 8/75
3 P 5/75 13/75
4 Q 3/75 16/75
5 P 5/75 21/75
6 Q 3/75 24/75
7 P 5/75 29/75
8 Q 3/75 32/75
9 P 5/75 37/75
10 Q 3/75 40/75'
11 P 5/75 45/75
12 Q 3/75 48/75
13 P 5/75 53/75
14 Q 3/75 56/75
15 P 5/75 61/75
16 Q 3/75 64/75
17 P 5/75 69/75
18 Q 3/75 72/75 [9 days each]
19 P 5/75 77/75 [ 77/75 is more than 75/75 = 1, so 19 days does it.]
Or, you could have used 9.375 to get 9 days each plus a little bit. 9 days each (18 days total) is
9*5/75 + 9*3/75 = (45+27)/75 = 72/75 and it is P's turn next.
Thus, 19 days is (72+5)/75 = 77/75, which is greater than 1. The work is done.