Arthur D. answered 10/29/14
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(4/5)(7y+3)=(5/3)+(3/6)(4y-2)
(28/5)y+(12/5)=(5/3)+2y-1
(28/5)y-2y=(5/3)-1-(12/5)
(5 3/5)y-2y=(25/15)-(15/15)-(36/15)
(3 3/5)y=(25-15-36)/15
(18/5)y=(-26/15)
(5/18)(18/5)y=(5/18)(-26/15)
y=(-130/270)
y=-13/27