four times the sum of three times a number increased by two is equal to three times the difference of two times the number decreased by eight

Question

four times the sum of three times a number increased by two is equal to three times the difference of two times the number decreased by eight

Answer 1

Let x = the unknown number.

 

Four times the sum of three times a number increased by two = 4*(3x+2)

 

is equal to three times the difference of two times the number decreased by eight = 3*(2x-8)

 

4*(3x+2) = 3*(2x-8)

 

Distribute:

 

4*3x + 4*2 = 3*2x - 3*8

12x + 8 = 6x - 24

 

Combine like terms:

 

6x = -32

 

Solve for x.