factor the expression: x(x-8)+(x-8)
Distribute or dissect the equation by applying multiplications:
x^2-8x+x-8 -->> x^2+x-8x-8
Now apply Factorization: --->> (X-8)(X+1)
factor the expression: x(x-8)+(x-8)
Distribute or dissect the equation by applying multiplications:
x^2-8x+x-8 -->> x^2+x-8x-8
Now apply Factorization: --->> (X-8)(X+1)
Think of factoring out a common factor from both terms: [x(x-8)+1(x-8)] factor out the (x-8) from both terms and we are left with (x-8)[x+1].
x(x-8) + (x-8)
Looking at you can see that (x-8) is in both terms if you replaced (x-8) with y you'd have
You can factor out the (x-8) as though it were a simple variable, because it is in () in the first term.
Hope this helps,
Steven P.
Distribute the x, combine like terms to get a trinomial, then factor.
Distribute: x(x-8) = x^{2}-8x
Combine: x^{2}-8x + (x-8) = x^{2}-7x - 8
Factor: x^{2}-7x - 8 = (x-8)(x+1)