factor the expression: x(x-8)+(x-8)

Distribute or dissect the equation by applying multiplications:

x^2-8x+x-8 -->> x^2+x-8x-8

Now apply Factorization: --->> (X-8)(X+1)

factor the expression: x(x-8)+(x-8)

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Distribute or dissect the equation by applying multiplications:

x^2-8x+x-8 -->> x^2+x-8x-8

Now apply Factorization: --->> (X-8)(X+1)

x(x-8) + (x-8)

Looking at you can see that (x-8) is in both terms if you replaced (x-8) with y you'd have

- x(x-8) + (x-8)
- xy + y = xy + 1y where y = x-8
- y(x+1) factor the y out
- (x-8)(x+1) simply replace y with it's original value of x-8.

You can factor out the (x-8) as though it were a simple variable, because it is in () in the first term.

Hope this helps,

Steven P.

Distribute the x, combine like terms to get a trinomial, then factor.

Distribute: x(x-8) = x^{2}-8x

Combine: x^{2}-8x + (x-8) = x^{2}-7x - 8

Factor: x^{2}-7x - 8 = (x-8)(x+1)

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