John does a calculation using the digits A, B, C and D. which digit is represented by B? ABC+CBA=DDDD

Question

pls explain the answers indetail

Answer 1

It may help to write the problem in the form:

\X Y

A B C

+ C B A

-----------

D D D D

Where X and Y are the "carry" digits

Now, it is reasonable to assume that neither A nor C are 0. This would make the number ABC to be BC and the number CBA to be BA.

The sum C+A is (YD). That is, put down D and carry Y. With digits 1-9, the value of Y is either 0 or 1.

The sum A+C is also (YD), but X+A+C is (DD). Of course, DDDD is not 0000, but it could be 1111 if B=0:

A B D

2 0 9

3 0 8

4 0 7

5 0 6

6 0 5

7 0 4

8 0 3

9 0 2

The value of B is 0.