
Patrick B. answered 12/22/18
Tutor
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(31)
Math and computer tutor/teacher
distance = rate x time
The distances are the same
90 t = 99 (t - 1/3) <--- 20 minutes is 1/3 hour
90 t = 99t - 33
-9 t = -33
t = -33/ -9 = 11/3
They will meet in 11/3 hr = 3 hours and 40 min
CHECK
90 (11/3) = 330
99 ( 10/3) = 330