An isosceles trapezoid has a perimeter of 41 inches. Its shorter base measures 12 inches and its longer base measures 17 inches. The two remaining sides have the same length; what is that length?

Answer 1

Given: isosceles trapezoid (the non-parallel sides are of equal length), Perimeter = 41 inches,

small parallel side = 12 in., larger parallel side = 17 in.

Let x be the length of one parallel side

Perimeter = 41 = 12 + 17 + x + x

41 = 29 + 2x

Subtract 29 from both sides: 41 - 29 = 2x

12 = 2x

x = 6

Answer: 6 inches

Answer 2

41 = 12 + 17 = 2x

Can you solve for x and answer?