David M. answered 12/24/18
Dave "The Math Whiz"
I am assuming that the second equation is written like this: (2x+19)/y=3
We have 2 unknowns, so we must have 2 equations to solve for this.
Eq. I: -7x+y=-19
Eq. II: (2x+19)/y=3--->y=(2x+19)/3
Use the substitution method. Put the value we obtained for y from Eq. II into Eq. I and solve for x:
-7x+y=-19 Eq. I
-7x+(2x+19)/3=-19 substituting for y
(-21x+2x+19)/3=(-19)(3)/3 multiply -7x and -19 by 3 to get the same denominators
-19x+19=-57 simplify
-19x=-57-19 subtract 19 from both sides to isolate the x term
-19x=-76 simplify
x=-76/-19 divide both sides by -19 to isolate x
x=4 solve for x
Use this value for x in Eq. II and solve for y:
y=(2x+19)/3 Eq. II
y=(2(4)+19)/3 substitute 4 for x
y=(8+19)/3
y=27/3
y=9 solve for y
Therefore, your answers are x=4 and y=9. You can verify your answers by using these values of x & y in both equations and find that they are correct.