marys salary in 2006 was $35,800. in 2007 she received a raise of $1230. assume she receives the same raise every year. what is mary´s salary in 2007, 2008, 2009,2010,2011, and 2012

Answer 1

Hi Kylie, given the starting salary of $35,600 and a yearly raise of $1230, you can use an arithmetic series to find the salary for any given year.

Arithmetic series:

A_n = A₀ + d * (n - 1)

Where:

A_n = the total of n years

A₀ = the initial salary

d = difference

n = number of years

Year A₀ d n A_n

------------------------------------------------------

2006 35,800 1230 1 35,800

2007 * * 2 37,030

2008 * * 3 38,260

2009 4 39,490

2010 5 40,720

2011 6 41,950

2012 7 43,950

Questions?