The sum of two numbers is 41 . The smaller number is 5 less than the larger number. What are the numbers?

Question

The sum of two numbers is 41

. The smaller number is 5

 less than the larger number. What are the numbers?

Answer 1

s is the small number and it’s value is l-5 because it is 5 less than the larger number.

l is the large number and it’s value is l.

Now add the values of s and l together so they equal 41.

41=l+l-5

41=2l-5

+5 +5

46=2l

/2 /2

23=l

Since we know the large number is 23, subtract it from 41 to find the small number.

s=41-23

s=18