Patrick B. answered 12/16/18
Math and computer tutor/teacher
x(x+10) = 24
x^2 + 10x - 24 = 0
( x + 12)(x - 2 ) =0
x+12 results in negative measures
x-2 = 0
x=2
width must be 2 or more
Thomas S.
asked 12/16/18A rectangle has the width x and its length is 10 inches greater than the width. For what values of x are the area of the rectangle greater or equal to 24 square inches?
Patrick B. answered 12/16/18
Math and computer tutor/teacher
x(x+10) = 24
x^2 + 10x - 24 = 0
( x + 12)(x - 2 ) =0
x+12 results in negative measures
x-2 = 0
x=2
width must be 2 or more
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