factor 16x^(6)-64x^(4)-x^(2)+4=0

Question

Need help solving this math question.

Answer 1

16x^4 ( x^2 - 4) - 1 * (x^2 - 4) = 0

(16x^4 - 1) ( x^2 - 4) = 0

(4x^2 - 1)(4x^2+1)(x+2)(x-2) = 0

(2x+1)(2x-1)(4x^2 + 1)(x+2)(x-2) = 0

The solutions are x = {+-1/2 , +- i*sqrt(2)/2, +-2 }